(-18t^2-1800)/(t^2+5*t+100)^2=0

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Solution for (-18t^2-1800)/(t^2+5*t+100)^2=0 equation: 



(-18t^2-1800)/(t^2+5t+100)^2=0



Domain of the equation: (t^2+5t+100)^2!=0

t∈R



We multiply all the terms by the denominator


(-18t^2-1800)=0

We get rid of parentheses

-18t^2-1800=0

a = -18; b = 0; c = -1800;
Δ = b2-4ac
Δ = 02-4·(-18)·(-1800)
Δ = -129600
Delta is less than zero, so there is no solution for the equation

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